lordoeuf
NAXJA Forum User
- Location
- Vancouver Island
Has anyone ever measured the torque required to remove these seized Cherokee front axle nuts? I've searched around various forums and people just talking about tightened torque and measuring torque with a breaker bar, but I haven't seen anyone measure the required torque on these really darn stuck axle nuts.
I have a 2' 1/2" breaker with an additional 1.5' for a cheater pipe, for lever arm of 3.5'. I figure with me jumping on the bar, that's probably 800+ ft-lbs. All it does is [eventually] break the breaker bar at the 1/2" drive connection. I've broken 2 now. I've heated the nut for 18 minutes with a propane torch and even tried that wacky candle wax trick, but no go. I hit it with an impact which is rated to remove nuts at 600 ft-lbs, but no go.
I've hammered the nut while spraying it with Liquid Wrench and other brands of penetrating oil, but nothing.
My question is not so much of what other ideas you might have, but how much torque is typically required in cases like this? 2000 ft-lbs? Has anyone measured it? Thanks.
I have a 2' 1/2" breaker with an additional 1.5' for a cheater pipe, for lever arm of 3.5'. I figure with me jumping on the bar, that's probably 800+ ft-lbs. All it does is [eventually] break the breaker bar at the 1/2" drive connection. I've broken 2 now. I've heated the nut for 18 minutes with a propane torch and even tried that wacky candle wax trick, but no go. I hit it with an impact which is rated to remove nuts at 600 ft-lbs, but no go.
I've hammered the nut while spraying it with Liquid Wrench and other brands of penetrating oil, but nothing.
My question is not so much of what other ideas you might have, but how much torque is typically required in cases like this? 2000 ft-lbs? Has anyone measured it? Thanks.